8v^2-16v-20=-10

Solution for 8v^2-16v-20=-10 equation:

8v^2-16v-20=-10

We move all terms to the left:

8v^2-16v-20-(-10)=0

We add all the numbers together, and all the variables

8v^2-16v-10=0

a = 8; b = -16; c = -10;
Δ = b2-4ac
Δ = -162-4·8·(-10)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24}{2*8}=\frac{-8}{16}
=-1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24}{2*8}=\frac{40}{16}
=2+1/2
$